## RS Aggarwal Class 8 Solutions Chapter 16 Parallelograms Ex 16B

These Solutions are part of RS Aggarwal Solutions Class 8. RS Aggarwal Solutions Class 8 Chapter 16 Parallelograms Ex 16B.

**Other Exercises**

- RS Aggarwal Solutions Class 8 Chapter 16 Parallelograms Ex 16A
- RS Aggarwal Solutions Class 8 Chapter 16 Parallelograms Ex 16B

**Questions Tick the correct answer in each of the following.**

**Question 1.**

**Solution:**

Answer = (c)

The diagonals of a rhombus are not necessarily equal but the diagonals in rectangle, square and isosceles trapezium are always equal.

**Question 2.**

**Solution:**

Answer = (c)

Each side of a rhombus

**Question 3.**

**Solution:**

Answer = (b)

The sum of adjacent angles of a || gm = 180°

2x + 25° + 3x – 5° = 180°

=> 5x + 20° = 180°

=> 5x = 180° – 20° = 160°

=> x = \(\\ \frac { 160 }{ 5 } \)

= 32°

**Question 4.**

**Solution:**

Answer = (a)

The diagonals in rhombus, kite intersect each other at right angles.

But the diagonals of parallelogram do not necessarily intersect at right angles.

**Question 5.**

**Solution:**

Answer = (c)

Let l = 4x, b = 3x,

Then (diagonal)² = l² + b²

=> (25)² = 16x² + 9x²

=> 25x² = 625

=> x² = 25

=> x = 5

=> l = 4x = 4 x 5 = 20cm

b = 3x = 3 x 5 = 15cm

Perimeter = 2(l + b) = 2 (20 + 15)

= 2 x 35 = 70 cm

**Question 6.**

**Solution:**

Answer = (d)

AP and BP are the bisector of ∠A and ∠B

Sum of two adjacent angles of a ||gm = 180°

or ∠A + ∠B = 180°

But ∠1 = \(\\ \frac { 1 }{ 2 } \) ∠A and ∠2 =\(\\ \frac { 1 }{ 2 } \) ∠B

∠1 + ∠2 = \(\\ \frac { 1 }{ 2 } \) ∠A + \(\\ \frac { 1 }{ 2 } \) ∠B

= \(\\ \frac { 1 }{ 2 } \) (∠A + ∠B)

= 180° x \(\\ \frac { 1 }{ 2 } \) = 90°

∠P = 180° – (∠1 + ∠2)

= 180° – 90° = 90°

**Question 7.**

**Solution:**

Answer = (b)

Let one adjacent angle = x

Then second angle (smallest) = \(\frac { 2 }{ 3 } x \)

x + \(\frac { 2 }{ 3 } x \) = 180°

= \(\frac { 5 }{ 3 } x \) = 180°

=> x = 180° x \(\\ \frac { 3 }{ 5 }\) = 108°

=> Smallest angle = 108° x \(\\ \frac { 2 }{ 3 }\) = 72°

**Question 8.**

**Solution:**

Answer = (a)

The diagonals of square, rhombus bisect the interior angle but the diagonals of a rectangle do not.

**Question 9.**

**Solution:**

Answer = (d)

Sides of a square are equal

2x + 3 = 3x – 5

=> 3x – 2x = 3 + 5

=> x = 8

**Question 10.**

**Solution:**

Answer = (c)

Let smallest angle = x

then largest angle = 2x – 24°

But x + 2x – 24° = 180°

=> 3x – 24° = 180°

=> 3x = 180° + 24 = 204°

=> x = \(\\ \frac { 204 }{ 3 }\) = 68°

largest angle = 180° – 68° = 112°

Hope given RS Aggarwal Solutions Class 8 Chapter 16 Parallelograms Ex 16B are helpful to complete your math homework.

If you have any doubts, please comment below. Learn Insta try to provide online math tutoring for you.

kripa gupta says

thnx