## RS Aggarwal Class 8 Solutions Chapter 12 Direct and Inverse Proportions Ex 12C

These Solutions are part of RS Aggarwal Solutions Class 8. Here we have given RS Aggarwal Solutions Class 8 Chapter 12 Direct and Inverse Proportions Ex 12C.

**Other Exercises**

- RS Aggarwal Solutions Class 8 Chapter 12 Direct and Inverse Proportions Ex 12A
- RS Aggarwal Solutions Class 8 Chapter 12 Direct and Inverse Proportions Ex 12B
- RS Aggarwal Solutions Class 8 Chapter 12 Direct and Inverse Proportions Ex 12C

**OBJECTIVE QUESTIONS :**

**Tick the correct answer in each of the following :**

**Question 1.**

**Solution:**

Answer = (d)

Cost of 14 kg of pulses = Rs 882

Cost of 1 kg of pulses Rs \(\\ \frac { 882 }{ 14 } \)

Cost of 22 kg of pulses = Rs \(\frac { 882\times 22 }{ 14 } \)

= 63 x 22

= Rs 1386

**Question 2.**

**Solution:**

Let x be oranges which can be bought for Rs. 33.80

8 : x : : 10.40 : 33.80

=> x × 10.40 = 8 x 33.80

=> \(\frac { 8\times 33.80 }{ 10.40 } \)

=> \(\frac { 8\times 3380 }{ 1040 } \)

= 26

∴ No. of oranges = 26 Ans. (c)

**Question 3.**

**Solution:**

No. of bottles 420 x

Time 3 5

More time, more bottles

By direct proportion

420 : x :: 3 : 5

x = \(\frac { 420\times 5 }{ 3 } \)

= 700

∴ No. of bottle will be 700 (b)

**Question 4.**

**Solution:**

Distance covered 75 km x

Time taken 60 min. 20 min.

Less time, less distance By direct proportion,

75 : x :: 60 : 20

x = \(\frac { 75\times 20 }{ 60 } \)

= 25

∴ Distance covered = 25 km (a)

**Question 5.**

**Solution:**

No. of sheets 12 : x

Weight 40 g : 1000 g

More weight, more sheets

By direct proportion 12 : x :: 40 : 1000

x = \(\frac { 12\times 1000 }{ 40 } \)

= 300

∴ No. of sheets = 300 (c)

**Question 6.**

**Solution:**

Let x be the height of tree

Height of pole 14 m : x m

Length of shadow 10 m : 7 m

Less shadow, less height

By direct proportion 14 : x :: 10 : 7

x = \(\frac { 14\times 7 }{ 10 } \)

= \(\\ \frac { 98 }{ 10 } \)

= 9.8 m

∴ Height of the = 9.8 m (b)

**Question 7.**

**Solution:**

Let actual length of bacteria = x cm

Enlarged (times) 50000

Length 5 cm

Then actual length (x)

Then \(\frac { x\times 50000 }{ -4 } \)

= 5

=> x = \(\\ \frac { 5 }{ 50000 } \)

= \(\\ \frac { 1 }{ 10000 } \)

= 10 cm (c)

**Question 8.**

**Solution:**

No. of pipes 6 : 5

Time taken to 120 min : x min

fill the tank

Less pipes, more time

By inverse proportion 6 : 5 :: x : 120

x = \(\frac { 6\times 120 }{ 5 } \)

= 144 (b)

∴ Time taken = 144 minutes

**Question 9.**

**Solution:**

Let number of days = x, then

Persons 3 : 4

(Time taken to build a wall) 4 : x

More person, less time take

By inverse proportion,

3 : 4 :: x : 4

x = \(\frac { 4\times 3 }{ 4 } \)

= 3 (b)

∴ Time taken to build the wall = 3 days

**Question 10.**

**Solution:**

Let time taken will be x hrs

Speed 60 km/h : 80 km/h

Time taken to 2hr : x

reach

(More speed, less time)

By inverse proportion 60 : 80 :: x : 2

x = \(\frac { 60\times 2 }{ 80 } \)

= \(\\ \frac { 3 }{ 2 } \)

∴ Time take \(\\ \frac { 3 }{ 2 } \) hours or 1 hr. 30 m in. (a)

Hope given RS Aggarwal Solutions Class 8 Chapter 12 Direct and Inverse Proportions Ex 12C are helpful to complete your math homework.

If you have any doubts, please comment below. Learn Insta try to provide online math tutoring for you.

Krishnam says

Thanks

Ishita says

How can we know that this question is inverse or direct

Arpitparihar says

Please made this rs solution in play store

Mirra Khanna says

Thank you R S sir this book made it easy for class 9 and 10 . Though i read in class 8

Thanks a lot😊