## RS Aggarwal Class 8 Solutions Chapter 11 Compound Interest Ex 11D

These Solutions are part of RS Aggarwal Solutions Class 8. Here we have given RS Aggarwal Solutions Class 8 Chapter 11 Compound Interest Ex 11D.

**Other Exercises**

- RS Aggarwal Solutions Class 8 Chapter 11 Compound Interest Ex 11A
- RS Aggarwal Solutions Class 8 Chapter 11 Compound Interest Ex 11B
- RS Aggarwal Solutions Class 8 Chapter 11 Compound Interest Ex 11C
- RS Aggarwal Solutions Class 8 Chapter 11 Compound Interest Ex 11D

**Tick the correct answer in each of the following**

**Question 1.**

**Solution:**

Principal (P) = Rs. 5000

Rate (R) = 8% p.a.

Period (n) = 2 years

**Question 2.**

**Solution:**

Principal (P) = Rs. 10000

Rate (R) = 10% p.a.

Period (n) = 3 years

**Question 3.**

**Solution:**

Principal (P) = Rs. 10000

Rate (R) = 12% p.a.

**Question 4.**

**Solution:**

Principal (P) = Rs. 4000

Rate (R) = 10% p.a.

Period (a) = 2 years 3 months

**Question 5.**

**Solution:**

Principal (P) = Rs. 25000

Rate (R1) = 5% for the first year

R2 = 6% for the second year

R3 = 8% for the third year

**Question 6.**

**Solution:**

Principal (P) = Rs. 6250

Rate (R) = 8% p.a. or 4% half yearly

Period (n) = 1 year or 2 half years

**Question 7.**

**Solution:**

Principal (P) = Rs. 40000

Rate (R) = 6% p.a. \(\\ \frac { 6 }{ 4 } \) = \(\\ \frac { 3 }{ 2 } \) % quarterly

Period (n) = 6 months = 2 quarters

**Question 8.**

**Solution:**

Present population (P) = 24000

Rate of increase (R) = 5% p.a.

Period (n) = 2 years

**Question 9.**

**Solution:**

3 years ago, the value of machine = Rs. 60000

Rate of depreciation (R) = 10%

Period (n) = 3 years

**Question 10.**

**Solution:**

Present value = Rs. 40000

Rate of depreciation (R) = 20% p.a.

Value of machine 2 years ago

**Question 11.**

**Solution:**

Rate of growth in population (R) = 10%

Present population = 33275

Population 3 years ago = A

**Question 12.**

**Solution:**

S.I. = Rs. 1200

Rate (R) = 5%

Period (T) = 3 years

**Question 13.**

**Solution:**

C.I. on a sum = Rs. 510

Rate (R) = \(12\frac { 1 }{ 2 } \) % = \(\\ \frac { 25 }{ 2 } \) % p.a.

Period (n) = 2 years

**Question 14.**

**Solution:**

Amount = Rs. 4913

Rate (R) = \(6\frac { 1 }{ 4 } \) = \(\\ \frac { 25 }{ 4 } \) %

Period (n) = 3 years

**Question 15.**

**Solution:**

Sum (P) = Rs. 7500

Amount (A) = 8427

Period = 2 years

Let R be the rate of p.a., then

Hope given RS Aggarwal Solutions Class 8 Chapter 11 Compound Interest Ex 11D are helpful to complete your math homework.

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Aditya says

You should add test paper of book also