## RS Aggarwal Class 8 Solutions Chapter 1 Rational Numbers Ex 1A

These Solutions are part of RS Aggarwal Solutions Class 8. Here we have given RS Aggarwal Solutions Class 8 Chapter 1 Rational Numbers Ex 1A.

**Other Exercises**

- RS Aggarwal Solutions Class 8 Chapter 1 Rational Numbers Ex 1A
- RS Aggarwal Solutions Class 8 Chapter 1 Rational Numbers Ex 1B
- RS Aggarwal Solutions Class 8 Chapter 1 Rational Numbers Ex 1C
- RS Aggarwal Solutions Class 8 Chapter 1 Rational Numbers Ex 1D
- RS Aggarwal Solutions Class 8 Chapter 1 Rational Numbers Ex 1E
- RS Aggarwal Solutions Class 8 Chapter 1 Rational Numbers Ex 1F
- RS Aggarwal Solutions Class 8 Chapter 1 Rational Numbers Ex 1G
- RS Aggarwal Solutions Class 8 Chapter 1 Rational Numbers Ex 1H

**Question 1.**

**Solution:**

(i) 20 = 5 x 4

\(\\ \frac { -3 }{ 5 } \) = \(\\ \frac { -3X4 }{ 5X4 } \)

(multiplying numerator and denominator by 4)

You can also Download NCERT Solutions for Class 8 Maths to help you to revise complete Syllabus and score more marks in your examinations.

**Question 2.**

**Solution:**

98 = 7 x 14

**Question 3.**

**Solution:**

60 = 5 x 12

**Question 4.**

**Solution:**

(i) \(\\ \frac { -12 }{ 30 } \)

H.C.F of 12 and 30 = 6

Dividing the numerator and denominator

**Question 5.**

**Solution:**

(i) \(\\ \frac { 3 }{ 8 } \) or 0

We know that every positive rational number is greater than 0.

∴\(\\ \frac { 3 }{ 8 } \) is greater

and clearly \(\frac{-1}{2} \) is greater. Ans.

**Question 6.**

**Solution:**

(i) \(\\ \frac { -4 }{ 3 } \) or \(\\ \frac { 8 }{ 7 } \)

Her,denominator are not same

LCM of 3 and 7 = 21

**Question 7.**

**Solution:**

(i) Between \(\\ \frac { -3 }{ 7 } \) and \(\\ \frac { 6 }{ -13 } \)

or \(\\ \frac { -3 }{ 7 } \) and \(\\ \frac { -6 }{ 13 } \)

LCM of 7 and 13 = 91

**Question 8.**

**Solution:**

Among, \(\\ \frac { 4 }{ -9 } \),\(\\ \frac { -5 }{ 12 } \),\(\\ \frac { 7 }{ -18 } \),\(\\ \frac { -2 }{ 3 } \) making their denominator positive,we get:

**Question 9.**

**Solution:**

(i)Among – 2,\(\\ \frac { -13 }{ 6 } \),\(\\ \frac { 8 }{ -3 } \),\(\\ \frac { 1 }{ 3 } \)

Making the denominator of \(\\ \frac { 8 }{ -3 } \) as

**Question 10.**

**Solution:**

(i) True, as the set of whole numbers is a subset of the set of rational numbers

(ii) True, as the set of integers is a subset of the set of rational numbers.

(iii) False, as 0 is a whole number and set of the whole number is a subset of rational numbers

∴ 0 is also a rational number.

Hope given RS Aggarwal Solutions Class 8 Chapter 1 Rational Numbers Ex 1A are helpful to complete your math homework.

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Pragyanand Narayan says

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aanshuman yadhuvanshi says

nyc sollution

thanks