## RS Aggarwal Class 7 Solutions Chapter 9 Unitary Method CCE Test Paper

These Solutions are part of RS Aggarwal Solutions Class 7. Here we have given RS Aggarwal Solutions Class 7 Chapter 9 Unitary Method CCE Test Paper.

**Other Exercises**

- RS Aggarwal Solutions Class 7 Chapter 9 Unitary Method Ex 9A
- RS Aggarwal Solutions Class 7 Chapter 9 Unitary Method Ex 9B
- RS Aggarwal Solutions Class 7 Chapter 9 Unitary Method Ex 9C
- RS Aggarwal Solutions Class 7 Chapter 9 Unitary Method CCE Test Paper

**Question 1.**

**Solution:**

Cost of 8 toys = ₹ 192

Cost of 1 toys = ₹ \(\frac { 192 }{ 8 }\) = ₹ 24

Cost of 14 toys = 24 x 14 = ₹ 336

**Question 2.**

**Solution:**

Distance covered with 15L of petrol = 270 km

Distance covered with 1L of petrol 270 = \(\frac { 270 }{ 15 }\) km

Distance covered with 8L of petrol 270 = \(\frac { 270 }{ 15 }\) x 8 km = 144 km

**Question 3.**

**Solution:**

Cost of 15 envelopes = ₹ 11.25

Cost of 1 envelope = ₹ \(\frac { 11.25 }{ 15 }\)

Cost of 20 envelopes = \(\frac { 11.25 }{ 15 }\) x 20 = ₹ 15

**Question 4.**

**Solution:**

24 cows can graze a field in = 20 days

1 cow can graze a field in = 20 x 24 days

15 cows can graze a field in = \(\frac { 20 x 24 }{ 15 }\)

= 32 days

**Question 5.**

**Solution:**

Time taken to finish the work by 8 men = 15 h

Time taken to finish the work by 1 man = 8 x 15 h

Time taken to finish the work by 20 men = \(\frac { 8 x 15 }{ 20 }\) h = 6 h

[More men, less time taken]

**Question 6.**

**Solution:**

Time taken to fill \(\frac { 4 }{ 5 }\) of the cistern = 1 min

Time taken to fill 1 cistern = \(\frac { 1 }{ \frac { 4 }{ 5 } }\) = \(\frac { 5 }{ 4 }\)

= 1.25 min = 1 min 15 sec

Hence, it will take 1 min 15 sec to fill the empty cistern.

**Question 7.**

**Solution:**

Time taken to cover the distance at a speed of 45 km/h = 3 h 20 min

Time taken to cover the distance at a speed of 1 km/h = 45 x 3.33 h

[Less speed, more time taken] (20 min = 0.33 hour)

Time taken to cover the distance at a speed of 50 km/h

= \(\frac { 45 x 3.33 }{ 50 }\) h

= 3h [More speed, less time taken]

**Question 8.**

**Solution:**

Number of days with enough food for 120 men = 30

Number of days with enough food for 1 man = 30 x 120 [Less men, more days]

Number of days with enough food for 100 men = \(\frac { 30 x 120 }{ 100 }\)

= 36 [More men, less days]

**Mark (✓) against the correct answer in each of the following :**

**Question 9.**

**Solution:**

(c) 644 km

1 cm represents km 80.5 cm represents = 8 x 80.5 = 644 km

**Question 10.**

**Solution:**

(a) 24 days

16 men can reap the field in 30 days.

1 man can reap the field in 30 x 16 days [Less men, more days]

20 men can reap the field in \(\frac { 30 x 16 }{ 20 }\)

= 24 days [More men, less days]

**Question 11.**

**Solution:**

(b) 49

Number of cows that eat as much as 15 buffaloes = 21

Number of cows that eat as much as 1 buffalo = \(\frac { 21 }{ 15 }\)

Number of cows that eat as much as 35 buffaloes = \(\frac { 21 }{ 15 }\) x 35 = 49

**Question 12.**

**Solution:**

Number of cows that graze the field in 12 days = 45

Number of cows that graze the field in 1 day = 45 x 12

Number of cows that graze the field in 9 days = \(\frac { 45 x 12 }{ 2 }\) = 60

**Question 13.**

**Solution:**

(b) ₹ 162

Cost of 72 eggs = ₹ 108

Cost of 1 egg = ₹ \(\frac { 108 }{ 72 }\)

Cost of 108 eggs = ₹ \(\frac { 108 x 108 }{ 72 }\)

= ₹ 162

**Question 14.**

**Solution:**

(i) 588 days

42 men can dig the trench in 14 days 1 men can dig the trench in = 42 x 14 = 588 days

(ii) ₹48

15 oranges cost ₹ 60

12 oranges will cost ₹ \(\frac { 60 }{ 15 }\) x 12 = ₹ 48

(iii) 10.8 kg

A rod of length 10m weighs 18 kg

A rod of length 6 m will weigh = \(\frac { 18 }{ 10 }\) x 6 = 10.8 kg

(iv) 3 h 12 min

12 workers finish the work in 4 h

15 workers will finish the work in \(\frac { 4 x 12 }{ 15 }\) = 3.2 h = 3h 12 min

**Question 15.**

**Solution:**

(i) False

10 pipes fill the tank in = 24 min.

1 pipe will fill the tank in = 24 x 10 min. [Less pipes, more time taken]

8 pipes will fill the tank in = \(\frac { 24 x 10 }{ 8 }\)

= 30 min. [More pipes, less time taken]

(ii) True

8 men finish the work in = 40 days

1 man finishes the work in = 8 x 40 days [Less men, more days taken]

10 men will finish the work in = \(\frac { 8 x 40 }{ 10 }\)

= 32 days [More men, less days taken]

(iii) True

A 6 m tall tree casts a shadow of length = 4 m.

Aim tall tree cast a shadow of length = \(\frac { 4 }{ 6 }\) m

A 75 m tall pole will cast a shadow of length = \(\frac { 4 }{ 6 }\) x 75 = 50 m

(iv) True

1 toy is made in = \(\frac { 2 }{ 3 }\) h. [Less toys, less time taken]

12 toys can be made in = \(\frac { 2 }{ 3 }\) x 12

= 8h [More toys, more time taken]

Hope given RS Aggarwal Solutions Class 7 Chapter 9 Unitary Method CCE Test Paper are helpful to complete your math homework.

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