## RS Aggarwal Class 7 Solutions Chapter 10 Percentage Ex 10B

These Solutions are part of RS Aggarwal Solutions Class 7. Here we have given RS Aggarwal Solutions Class 7 Chapter 10 Percentage Ex 10B.

**Other Exercises**

- RS Aggarwal Solutions Class 7 Chapter 10 Percentage Ex 10A
- RS Aggarwal Solutions Class 7 Chapter 10 Percentage Ex 10B
- RS Aggarwal Solutions Class 7 Chapter 10 Percentage Ex 10C
- RS Aggarwal Solutions Class 7 Chapter 10 Percentage CCE Test Paper

**Question 1.**

**Solution:**

Rupesh seemed 495 marks out of 750

Percentage of marks = \(\frac { 495 }{ 750 }\) x 100 = 66%

**Question 2.**

**Solution:**

Monthly salary = Rs. 15625

Increase = 12%

Amount of increase = \(\frac { 15625 x 12 }{ 100 }\) = Rs. 1875

New salary = Rs. 15625 + Rs. 1875 = Rs. 17500

**Question 3.**

**Solution:**

Excise duty in the beginning = Rs. 950

Reduced duty = Rs. 760

Reduction = Rs. 950 – Rs. 760 = Rs. 190

Reduction percent = \(\frac { 190 x 100 }{ 950 }\) = 20%

**Question 4.**

**Solution:**

Let x be the total cost of the T.V

96% of x = 10464

Total cost of T.V = Rs. 10900

**Question 5.**

**Solution:**

Let number of students = x

In a school boys = 70%

girls = 100 – 70 = 30%

Now 30% of x = 504

Number of boys = 1680 – 504 = 1176

and number of total students = 1680

**Question 6.**

**Solution:**

Copper required = 69 kg

copper in ore = 12%

Let quantity of ore = x kg

12% of x = 69

Quantity of ore = 575kg

**Question 7.**

**Solution:**

Pass marks = 36%

A students gets marks = 123

But failed by 39 marks

Pass marks = 123 + 39 = 162

Now, 36% of maximum marks = 162

Maximum marks = \(\frac { 162 x 100 }{ 36 }\) = 450 marks

**Question 8.**

**Solution:**

Let number of apples = x

Number of apples sold = 40% of x

Hence number of apples = 700

**Question 9.**

**Solution:**

Let total number of examinees = x

the numbers of examinees who passed = 72% of x

= \(\frac { x x 72 }{ 100 }\)

= \(\frac { 18x }{ 25 }\)

**Question 10.**

**Solution:**

Let the gross value of moped = x

Amount of commission = 5% of x

**Question 11.**

**Solution:**

Total gunpowder = 8 kg

Amount of nitre = 75%

amount of sulphur = 10%

Rest of powder which is charcoal = 100 – (75 + 10) = 100 – 85 = 15 = 15%

Amount of charcoal = 8 x \(\frac { 15 }{ 100 }\) = \(\frac { 120 }{ 100 }\)

= \(\frac { 6 }{ 5 }\) kg = 1 kg 200 grams = 1.2 kg

**Question 12.**

**Solution:**

Quantity of chalk = 1 kg or 1000 g

**Question 13.**

**Solution:**

Let total number of days on which the

school open = x

and Sonal’s attendance = 75%

x x 75% = 219

No. of days on which was school open = 292 days

**Question 14.**

**Solution:**

Rate of commission = 3%

Amount of commission = Rs. 42660

Let value of property = x

then 3% of x = 42660

**Question 15.**

**Solution:**

Total votes of the constituency = 60000

Votes polled = 80% of total votes

= \(\frac { 80 }{ 100 }\) x 60000 = 48000

Votes polled in favour of A = 60% of polled votes

= \(\frac { 60 }{ 100 }\) x 48000 = 28800

Votes polled in favour of B = 48000 – 28800 = 19200

**Question 16.**

**Solution:**

Let original price of shirt = Rs. x

Discount = 12%

Original price of shirt = Rs. 1350

**Question 17.**

**Solution:**

Let original price of sweater = x

Rate of increase = 8%

Increased price = x + 8% of x

Hence, original price of sweater = Rs. 1450

**Question 18.**

**Solution:**

Let total income = x

**Question 19.**

**Solution:**

Let the given number = 100

Then increase % = 20%

Decrease = 100 – 96 = 4

Decrease per cent = 4%

**Question 20.**

**Solution:**

Let original salary of the officer = Rs. 100

Increase = 20%

**Question 21.**

**Solution:**

Rate of commission = 2% on first Rs. 200000

1 % on next Rs. 200000 and 0.5% on remaining price

Sale price of property = Rs.200000 + 200000 +140000 = Rs. 540000

Now commission earned by the

= Rs. 200000 x 2% + Rs. 200000 x 1% + 140000 x 0.5%

**Question 22.**

**Solution:**

Let Akhil’s income = Rs. 100

Then income of Nikhil’s will be = Rs. 100 – 20 = Rs. 80

Amount which is more than that of Akhil’s = 100 – 80 = Rs. 20

% age = \(\frac { 20 x 100 }{ 80 }\) = 25%

**Question 23.**

**Solution:**

Let income of Mr Thomas = Rs. 100

then income of John = Rs. 100 + 20 = Rs. 120

Income of Mr Thomas is less than John = Rs. 120 – 100 = Rs. 20

% age = \(\frac { 20 x 100 }{ 120 }\)

= \(\frac { 50 }{ 3 }\) = 16\(\frac { 2 }{ 3 }\) %

**Question 24.**

**Solution:**

Present value of machine = Rs. 387000

Rate of depreciation = 10%

Let 1 year ago the value of machine was = x

1 year ago, value of machine = Rs. 430000

**Question 25.**

**Solution:**

Present value of car = Rs. 450000

Rate of decreasing of value = 20%

Value after 2 years

**Question 26.**

**Solution:**

Present population = 60000

Rate of increase = 10%

Increased population after 2 years

**Question 27.**

**Solution:**

Let the price of sugar = Rs. 100

and consumption = 100 kg.

Increase price of 100 kg = Rs. 100 + 25 = Rs. 125

Now increased amount on 100 kg = Rs. 125

Hope given RS Aggarwal Solutions Class 7 Chapter 10 Percentage Ex 10B are helpful to complete your math homework.

If you have any doubts, please comment below. Learn Insta try to provide online math tutoring for you.

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